A function y=f(x) can be parametrized by setting:
x(t)=t,y(t)=f(t)
Solve for t in terms of x, then substitute into the equation for y.
dydx=dydtdxdt
d2ydx2=ddt(dydx)÷dxdt
If a smooth curve x=f(t),y=g(t) is traced from a to b, then the arc length is:
L=∫ba√(dxdt)2+(dydt)2dt
The Cartesian and Polar coordinates are related as:
x=rcosθ,y=rsinθ,x2+y2=r2,tanθ=yx
If a curve is given by r=f(θ), the slope is:
dydx=drdθsinθ+rcosθdrdθcosθ−rsinθ
The area of a region enclosed by r=f(θ) is:
A=12∫βαr2dθ
u+v=⟨x1+x2,y1+y2⟩,kv=k⟨x,y⟩=⟨kx,ky⟩
The velocity and acceleration vectors are:
v(t)=⟨x′(t),y′(t)⟩,a(t)=⟨x″(t),y″(t)⟩
The speed along the curve is the magnitude of the velocity vector:
|v|=√x′(t)2+y′(t)2
The displacement vector from t=a to t=b is:
⟨∫bax′(t)dt,∫bay′(t)dt⟩
The total distance traveled is:
∫ba|v(t)|dt=∫ba√x′(t)2+y′(t)2dt