Solution

The system of equations is given as:

920by+715=920ax920by+715=920ax x8+y18=a2+5x12x8+y18=a2+5x12

We are tasked with finding the value of abab.

Solution:

Rewriting the first equation: 27by+28=27ax27by+28=27ax and rearranging: 27ax+27by=2827ax+27by=28(1)

For the second equation, after multiplying through by the LCM of denominators, we get: 21x+4y=36a21x+4y=36a(2)

Solving the system of equations, from Equation (1): 27a21=2836a Simplifying: 972a2=588 a2=4981a=79

From Equation (1) substituting a: b=427

Finally, the value of ab is: ab=79(427) Simplifying: ab=2127+427=2527

Answer: C) 2527