The system of equations is given as:
920by+715=−920ax920by+715=−920ax x8+y18=a2+5x12x8+y18=a2+5x12
We are tasked with finding the value of a−ba−b.
Solution:
Rewriting the first equation: 27by+28=−27ax27by+28=−27ax and rearranging: 27ax+27by=−2827ax+27by=−28(1)
For the second equation, after multiplying through by the LCM of denominators, we get: −21x+4y=36a−21x+4y=36a(2)
Solving the system of equations, from Equation (1): 27a−21=−2836a Simplifying: 972a2=588 a2=4981⟹a=79
From Equation (1) substituting a: b=−427
Finally, the value of a−b is: a−b=79−(−427) Simplifying: a−b=2127+427=2527
Answer: C) 2527